p^2-14p-45=0

Solution for p^2-14p-45=0 equation:

p^2-14p-45=0

a = 1; b = -14; c = -45;
Δ = b2-4ac
Δ = -142-4·1·(-45)
Δ = 376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{376}=\sqrt{4*94}=\sqrt{4}*\sqrt{94}=2\sqrt{94}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{94}}{2*1}=\frac{14-2\sqrt{94}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{94}}{2*1}=\frac{14+2\sqrt{94}}{2}
$